设a<sub>1</sub>,a<sub>2</sub>...a<sub>s</sub>是s个n维向量,下列论断正确的是().

A.a,不能由a<sub>1</sub>,a<sub>2</sub>...a<sub>s-1</sub>线性表出,则向量组a<sub>1</sub>,a<sub>2</sub>...a<sub>s</sub>线性无关 B.已知存在不全为零的数k<sub>1</sub>,k<sub>2</sub>.....k<sub>s-1</sub>使得<img src='https://img2.soutiyun.com/ask/2021-03-04/983720401819059.png' />则a<sub>s</sub>不能由a<sub>1</sub>,a<sub>2</sub>...a<sub>s-1</sub>线性表出 C.a<sub>1</sub>,a<sub>2</sub>...a<sub>s</sub>线性相关,则任一向量均可由其余向量线性表出 D.a<sub>1</sub>,a<sub>2</sub>...a<sub>s</sub>线性相关,as不能由a<sub>1</sub>,a<sub>2</sub>...a<sub>s-1</sub>线性表出,则a<sub>1</sub>,a<sub>2</sub>...a<sub>s-1</sub>线性相关

时间:2024-07-01 17:08:56

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