证明:者y<sub>1</sub>(x)是y"+py'+qy=f1(x)的解,而y<sub>2</sub>(x)是y"+py'+qy=f(x)的解,

证明:者y<sub>1</sub>(x)是y"+py'+qy=f1(x)的解,而y<sub>2</sub>(x)是y"+py'+qy=f(x)的解,则y<sub>1</sub>(x)±y<sub>2</sub>(x)必是方程<img src='https://img2.soutiyun.com/ask/2020-12-13/976736941521245.png' />的解. 特别,若y<sub>1</sub>(x)和y<sub>2</sub>(x)都是方程y"+py'+qy=f(x)的解,则它们的差y<sub>1</sub>(x)-y<sub>2</sub>(x)必是对应齐次方程y"+py'+qy=0的解.

时间:2023-02-14 16:20:21

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