Attention is ()the advice on the use of charts in The Mariner’s Handbook Chapter 3,Section 1.
When connecting to an 802.11a access point,which transmitter power selections can be chosen in the adu?()
The emergency communication set’s transmitter should not be tested except when()by a public radio inspector.
设a=3,b=2,c=-3,则表达式Abs(b+c)+a*Int(Rnd+3)+Asc(Chr(65+a))的值是()。
“The defective transmitter caused us a lot of trouble”中的a lot of trouble表示()。
When connecting to an 802.11a access point, which transmitter power selections can be chosen inthe ADU?()
int a=1,b=2,c=3;if(a>c)b=a;a=c;c=b;则c的值为2.
int a=1,b=2,c=3;if(a>b)a=b;if(a>c)a=c;则a的值为3.
当a=1,b=2,c=3时,执行以下程序段后a=【1】.if(a>c)b=a;a=c;c=b;
设整型变量a=1, b=2, c=3, d=4写出下列逻辑表达式的值: (1)a && b && c (2)a || !b || !c (3)++a || b++ && ++c || d++ (4)(!(a+b)+c-1)&& (b+c/2) (5)a !=11 && b<4
若a的值为3时,下列程序段被执行后,c的值为()。c=1;If (a>0)If (a>3)c=2;elsec=3;elsec=4;
设a=2,b=3,c=4,d=5,表达式3>2*b or a=c and b<>c or c>d的值是( )。
设a=2,b=3,c=4,求下列表达式的值:①a==3②a=3③a&&b④a||b+c&&b-c⑤!((a
如下程序的输出结果是 。 main( ) { int a=1,b=2,c=3; if(a>c) b=a; a=c; //a=3 c=b; //c=2 printf(\a=%d,b=%d,c=%d\\n\,a,b,c); }
如果int a=1,b=2,c=3,d=4;则条件表达式“a<b?a:c<d?c:d”的值是()。A)1 B)2C)3 D)4
a,b,c为整数,如果a+b+c能被6整除,则a<sup>3</sup>+b<sup>3</sup>+c<sup>3</sup>能被6整除.
设集合A={1,2,3},B={2,3,4},C={3,4,5},则A∩(C-B)={1,2,3,5}。()
若a的值为3时,下列程序段被执行后,c的值是()。intc=1;if(a>0)if(a>3)c=2;elsec=3;elsec-4;A.1B.2C
进入模型表明一个给定行业的企业越多,长期的行业供给曲线就越倾斜还是越平坦?entry presented in this chapter implies that the more firms in a given industry, the(steeper,flatter) is the long-run industry supply curve.
结合“自建课程PPT+录音+MOOC视频”授课、作业案例教学讨论、课后答疑 2、结合本课程第三章,自学MOOC视频Chapter 3 Balance of Payments 3、思考第4章教材P105-108页课后作业及案例题目,教材P105-106页question1、2、3、4、5、6要求交电子版答案作业,其余自己思考
已知向量a={3,5,-1},b={2.2.3},c={4,-1,-3}则a+b+c=(),ma+nb=().
若a的值为3,则下面的Java程序段被执行后,c的值是多少?()if (a>0 )if (a>3 )c = 2;elsec = 3;else c = 4;
设U={1,2,3,4,5,6,7},A={2,3,4},B={3,6,7},求A<sup>C</sup>,B<sup>C</sup>,A<sup>C</sup>∩B<sup>C</sup>,(A∪B)<sup>C</sup>.
若a的值为3时,下列程序段被执行后,c的值是多少?() c = 1; if (a>0 ) if (a>3 ) c = 2; else c = 3; else c = 4;